What is the ideal effort force for a wheel with a radius of 0.20 m and an axle radius of 0.05 m, lifting a load of 200 N?

To determine the ideal effort force for a wheel and axle system, you can use the principle of mechanical advantage. The mechanical advantage of a wheel and axle is given by the ratio of the radius of the wheel to the radius of the axle.

In this example, the radius of the wheel is 0.20 meters, and the radius of the axle is 0.05 meters. The mechanical advantage (MA) can be calculated as follows:

MA = Radius of Wheel / Radius of Axle = 0.20 m / 0.05 m = 4.

This means that the wheel and axle system will multiply the effort force by a factor of 4. To lift a load of 200 N, you need to divide the load by the mechanical advantage:

Effort Force = Load / MA

Effort Force = 200 N / 4 = 50 N.

This calculation shows that the ideal effort force required to lift a 200 N load using this wheel and axle system is 50 N. Understanding the mechanical advantage is crucial in determining how much force is needed to lift a given load efficiently, and the calculations confirm that the answer correctly reflects the physical principles at hand.