What is the parallel component of weight for a 300 N object on a 20° incline?

To determine the parallel component of weight for an object on an incline, we need to use the formula that relates the weight of the object and the angle of the incline. The parallel component of the weight can be calculated using the following equation:

[ W_{\parallel} = W \sin(\theta) ]

where ( W ) is the weight of the object and ( \theta ) is the angle of the incline.

In this case, we have a weight ( W ) of 300 N and an incline angle ( \theta ) of 20°.

First, we calculate the sine of 20°:

[ \sin(20°) \approx 0.342 ]

Next, we substitute the values into the equation:

[ W_{\parallel} = 300 , \text{N} \cdot 0.342 ]

Calculating this gives:

[ W_{\parallel} \approx 300 , \text{N} \cdot 0.342 \approx 102.6 , \text{N} ]

Rounding this value gives us approximately 102 N, which corresponds to the answer provided. This value represents the component of the weight of the object acting parallel