What is the required effort to lift a 30 N load with an effort arm of 0.50 m and a load arm of 0.10 m?

To determine the required effort to lift a load using a lever, you can apply the principle of moments, which states that for a lever in equilibrium, the moment (or torque) about the pivot must balance. This means that the effort times the effort arm must equal the load times the load arm.

In this scenario, you have a 30 N load and the lengths of the effort arm and load arm are 0.50 m and 0.10 m, respectively. The equation to balance the moments around the pivot is:

Effort × Effort Arm = Load × Load Arm.

Substituting the known values into the equation gives:

Effort × 0.50 m = 30 N × 0.10 m.

Calculating the right side, you find:

30 N × 0.10 m = 3 N·m.

Now, setting the two sides equal, you have:

Effort × 0.50 m = 3 N·m.

To find the effort, divide both sides by 0.50 m:

Effort = 3 N·m / 0.50 m = 6 N.

Thus, the required effort to lift the 30 N load is 6 N,